For four points to be concyclic, they must be the vertices of a cyclic quadrilateral. If two opposite angles of a quadrilateral sum to 180º it is cyclic. This is what I will show below.
Call the centers of the circles in order A, B, C, D. Call points of tangency W,X,Y,Z so that we can draw quadrilaterals ABCD and WXYZ.
Being a quadrilateral makes angles A+B+C+D=360
There are 4 isosceles triangles which allow us to find:
Angle AWZ = 180-A/2
Angle BWC = 180-B/2 etc.
Angle ZWX = 180-(A+B)/2
Angle XYZ = 180-(C+D)/2 etc.
Angles ZWX and XYZ are the opposite angles mentioned in the first paragraph. Their sum is
360-(A+B+C+D)/2 = 360 - 360/2 = 180
QED
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Posted by Jer
on 2013-07-04 01:27:18 |
Solution
