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Four Digits (Posted on 2013-11-05) Difficulty: 2 of 5
You have a number where any digit appears at most twice. The sum of all neighboring four digits in this number is a square number.

What is the maximum possible value for this number?

Example: 205290 is such a number because no digit appears more than twice and 2+0+5+2, 0+5+2+9, and 5+2+9+0 are square numbers.

No Solution Yet Submitted by Danish Ahmed Khan    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution possible solution...spoiler | Comment 1 of 4

I believe

987108719     IS THE BIGGEST POSSIBLE.<o:p></o:p>


  Posted by Ady TZIDON on 2013-11-05 13:07:33
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