Each letter of the alphabet has been assigned a different value from 1 to 26. The total values of the letters contained in a given word are as given below. Determine the value assigned to each letter of the alphabet.

BEG = 59            CALL = 48         CHIEF =  36           CRAZY =  60 
DEN = 53            GAME =  47        GUN = 51              HAM = 16
HAVE =  40          IF = 11           JACK = 24             KEY =  43
LAZE = 57           MAP =  28         MOVE = 58             NEON = 86
OXEN = 82           PALM = 47         QUIT = 40             QUITE = 60 
STALL = 80          TALK = 39         TORE = 73             VAST = 51
WALK = 54

*** Pen and Paper solution only.

(In reply to re: Solution by Ady TZIDON)

Detailed sequence is as follows

First from (QUIT,QUITE) E=20 and (MAP,PALM) L=19 substituting we get

BG=39,DN=33,HAV=11,AZ=18,OXN=62,STA=42,WAK=35,

CA=10,GAM=27,TAK=20,CH=5,MOV=38,TOR=53,KY=23,NON=66

Second (STA,VAST) give V=9

substituting we get HA=11, MO=29

Third (HAM,HA) gives M=5, (NON,MO) gives N=21 & O=24 and DN gives D=12 and OXN gives X=17

substituting we get GA=22,AP=23,GU=30,TR=29,

CH=5 ( options are 1 &4 or 2,3 ) since HA=11 and CA=10

so C=2, H=3 and A=8

substituting we get P=15(AP), Z= 10(AZ), G=14(GA), B=25(BG), U=16(GU), TK=12, JK=10, ST=34,WK=27,JK=14, RZY=50, QIT=24

only value of K that satisfies all letters considering remaining number is K=1,

then Y=22, T=11, W=26, J=13 and S=23, R=18, Z=10

We are left with IF=11, QI=13 so I=7, F=4 & Q=6

I hope I was clear.

 

Posted by Salil on 2013-12-04 06:08:17