Let n be a positive integer. By removing the last three digits of n, one gets the cube root of n. Find a possible value of n.

If the 5 digit number n=r^3 begins by ab and the truncated part  is cde, ab is ( more than 1000) times less than n.

It is also n^2 times less than n.

Take ( more than 1000)=1024  = 32 squared

and therefore ab=32 and abcde=32*1024=30768

Clearly , there are no other solutions.

Posted by Ady TZIDON on 2014-02-11 11:29:03