A woman's "measurements" are three numbers that measure, in order, the inches around her bust, waist and hips.
Now, a certain beauty contest winner had a 36-23-34 figure.
Although no two contestants had exactly the same measurements, the two runners-up differed by less than an inch in each measurement from the winner and the waist of each was two-thirds the hips of the other.

If the sum of the three measurements was the same for all three girls, what were the vital statistics of the two runners-up (the tape is accurate to only a quarter of an inch)?

Each woman's measurements equal 93.
One of the runners-up had measurements of 36.5-22-34.5. The other had measurements of 37-23-33. (22=33*2/3)(23=34.5*2/3)

Posted by Clinton Heath on 2003-05-28 09:26:47