A piece of paper TUVW has the precise shape of a square, with each side length being 20 units. The point M is the midpoint of side TU and N is the midpoint of TW.

The paper is now folded along the line MN such that the point T touches the paper. The point V is then folded over a line PQ parallel to MN such that V lies on MN.

Determine the area of the hexagon NMUPQW.

(In reply to Solution, I think by tomarken)

Rotate your triangles and you don't even need the sqrt(2).

Posted by Bractals on 2014-05-06 15:50:48