Under French law, the Beaujolais Nouveau
( wine ) is released at
12:01 A.M. on the third Thursday in November every year.
Last year, prior to the above date 11 wine amateurs deposited 12 small-size barrels at their merchant’s store (A,B,C,D,E,F,G - 7 liters each; S,T,U - 5 liters each and V two barrels: one 7 liters and one 5 liters).
When the wine arrived 70 liters were poured in the above barrels so that each barrel got an integer number of liters. The Customers were billed accordingly.
If every possible distribution of wine among the 12 barrels is equally likely, what is the possibility that V(ictor) had to pay for 11 liters of wine?
(In reply to
One second thought ... by Steve Herman)
It is a good idea to consider 6 missing liters instead of 70 present.
However to calculate the requested probability you need:
a. to find the quantity of partitioning 6 among 12 barrels, taking care of capacity limitations .
b, to find the quantity of partitioning 5 among 10 barrels, taking care of capacity limitation.
c.divide double the result of b (2 ways of the missing liter - V's two different barrels ) by the result of a.
Once you perform these tasks, I will compare it with my result and find out whether my calculations were faultless or not.
I do not see any shortcuts instead of the above procedure.
.
re: One second thought ... one hint.(partial spoiler)...
