Not recognizing a pattern in the series, I submit an answer for where a pattern, of a sorts, does exist:
The last number is 500.
200 < 519 > 442 : 2, 4, 6 (ascending even numbers)*
212 > 201 < 500 : 5, 3, 1 (descending odd numbers)**
*
200 = CC (2 digits); 519 = DXIX (4 digits); 442 = CDXLII (6 digits)
**
212 = CCXII (5 digits); 201 = CCI (3 digits); 500 = D (1 digit)
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Posted by Dej Mar
on 2015-01-02 10:42:23 |