Let
pr=(1/2)*(3/4)*(5/6)... *(99/100)
Without explicit computation prove that
pr is less than 1/10, but more than 1/15.
pr is as defined.
Let ps = 2/3*4/5*6/7.....98/99, clearly a larger number.
then pr*ps=1/100
So (pr)^2<1/100; so pr<1/10.
The second part is harder. From Weisstein on double factorials,
pr = (2n)!/(2^n*n!)^2, ps = (2^(2(n-1)) ((n-1)!)^2)/((2n-1)!)
and pr exceeds 0.6 of ps even for small pr. So 5/3x^2 = 1/100 and x is greater than 0.7, which is more than 1/15.
Edited on February 13, 2015, 12:59 pm
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Posted by broll
on 2015-02-13 12:28:19 |