Consider
S1=9 = 1! + 2! + 3!
S2=27 = 1! + 2! + 4!
S3=32 = 2! + 3! + 4!
The S1, S2, S3 represent the values of integer powers that can be represented as a sum of exactly three distinct factorials (0! excluded)
Find S4, S5, S6.
A friendly tip: STOP after S6.
(In reply to
re: Thoughts from OEIS by Charlie)
Ah yes. In retrospect, that hasty comment about finding large values was completely off the mark. Duh. You'd have to check whether each is a power by actually factoring the number.
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Posted by Jer
on 2015-04-17 21:13:39 |