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Find the lowest n (Posted on 2015-06-22)

Are there distinct positive integers a,b,n for which:
1/n = 1/a^2+1/b^2,
?

If so, find the triplet with lowest n.

No Solution Yet Submitted by Ady TZIDON

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| Comment 1 of 4

Yes, there are.

The smallest I have found are 5,10,20 and 10,5,20.

1/25 + 1/100 = 5/100 = 1/20

Smaller n might be possible, but I doubt it

Posted by Steve Herman on 2015-06-22 12:33:26

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