Find the possible outcomes of the following algorithm:
1.Take a random positive integer, divisible by three.
2.Consider its base 10 digits.
3.Take the sum of their cubes.
4.Go back to step 2.
Rem: You may limit your research for n<1000.
re: non-analytic solution
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(In reply to
non-analytic solution by Paul)
don't know enough about ruby to determine where you went wrong with your code. However, consider 25
2^3+5^3=133
1^3+3^3+3^3=55
5^3+5^3=250
2^3+5^3=133
and thus it will cycle indefinitely and never reach 153 as you proposed.
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Posted by Daniel
on 2015-09-18 00:52:10 |
