perplexus.info :: Games : Rook Placement

Rook Placement (Posted on 2015-09-21)

We place 41 rooks on a 10 x 10 chessboard. Prove that one can choose five of them that do not attack each other.

*** Two rooks "attack" each other if they are in the same row or column of the chessboard.

Source: A problem appearing in Colorado Mathematical Olympiad.

See The Solution Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re: the “official” solution - spoiler

| Comment 4 of 5 |

(In reply to the “official” solution - spoiler by Ady TZIDON)

Thanks, Ady, for the clear and witty editing of the "official" solution.

The counter-example that you requested is having all of the rooks in 4 rows (or having them all in 4 columns). With 40 rooks so placed, no set of 5 rooks can be found that do not attack each other. By the pigeonhole principle, if they are all in 4 rows, then at least two of them must be in the same row.

Posted by Steve Herman on 2015-09-27 06:39:20

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info