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Number machine problem 1 (Posted on 2003-06-08) Difficulty: 1 of 5
I have a number machine. I say x gives y if when x goes in, y comes out. For any numbers x and y, by "xy" I mean x followed by y. Here are my two rules.

1x gives x.
For example, 13 gives 3.
If x gives y, then 2x gives yy.
For example, 213 gives 33 since 13 gives 3.

What is a number that gives itself?

See The Solution Submitted by Tim Axoy    
Rating: 3.7000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
It is... | Comment 6 of 12 |
...2121.
Since 121 gives 21,2121 gives 2121.
We can find an i such that for any number x,ix gives xx,so ii will give itself.
21x gives xx since 1x gives x,and so 21 is an i.
2121 must give itself.
Good problem,Tim.
  Posted by John Tate on 2003-06-08 11:18:11
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