perplexus.info :: Numbers : Variety of divisors

Home > Numbers

Variety of divisors (Posted on 2015-12-03)

Find the smallest positive integer having divisors ending in 0, 1, 2, 3, ... 8, 9.

No Solution Yet Submitted by Ady TZIDON

No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)

re: solution

| Comment 2 of 4 |

(In reply to solution by broll)

270 isn't divisible by 7 or 8.

I started with 9 and 7 since they're smaller than 19 and 17. A 5 is needed and a 4 gets us 2, 2*3=6, 2*5=10, 2*9=18. That makes 4*5*7*9=1260.

Posted by xdog on 2015-12-03 11:48:49

Please log in:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info