(In reply to
re: pseudo-solution by Math Man)
Another pseudosolution: m=2 n=3
m n
1 0 2
0 1 3
1 1 5
1 1 5
-----
1 2 8
2 2 10
3 2 12
----
2 3 13
4 3 17
6 3 21
----
The patterns here are:
m goes 111,123,246, now should be 369.
n goes 111,222,333, now should be 444 or if follows F terms 555
So two pseudosolutions m=3 n=4 next term =18 or m=3 n=5 next = 21
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Posted by armando
on 2016-05-22 04:46:28 |