I have 6 pieces of candy: two each of 3 different colors. They taste especially good if eaten two at a time, provided the colors are different.

These candies are in an opaque bag from which I pick two at a time. If they are different colors I eat them together (yum) but if they are the same I put them back in and draw again. I will repeat this process to eat two more.

What is the probability the last two candies will be of differing colors?

Repeat with two each of 4 colors.
Repeat with two each of 5 colors.

(In reply to first part by armando)

There are IMHO 12 choices, 10 in favor of yum-yum , 2 against

So the probability  that the last two candies are of different colors is 10/12=5/6=.833333....

Posted by Ady TZIDON on 2016-05-25 11:33:18