Can a square having a side length of 2.1 be completely covered by seven squares each having a side length of 1?
What is the longest possible side length of the square satisfying the given conditions?

Provide adequate reasoning for your answer.

(In reply to One arrangment by Brian Smith)

It's not hard to calculate the largest square this arrangement can cover:

3/2 + sqrt(2)/2 or about 2.2071

I'm pretty sure there's no better arrangement.

Posted by Jer on 2016-06-24 12:11:28