ABC + DEF = GHI
GDA + HEB = IFC
There are two sets of simultaneous solutions for the above 2 alphametics,
one being a 90o rotation of the other.
Find both.
No leading zeroes.
(In reply to
program and solution (spoilers) by Charlie)
Your solution as well as the remark that it is not a "rotation" relation are correct.
Both sets of solutions are zeroless and the division of the 9 digits (= 3 triplets) in both is fitting your description.
b=8, i =9, d=1 in both while (c,h )=(2,3) in one and (3,2) in other, and (a,e) ,(f,g) correspond in similar way to (4,5), (7,6) accordingly.
So "one man's column is another man's row, ignoring order,"
Tnx for your correction.
re: program and solution (spoilers)
