Call an integer a two-three integer if it is greater than 1 and has the form 2
a * 3
b, where a ≥ 0 and b ≥ 0.
Express 19992000 as a sum of two-three integers so that none of the addends divides another.
Source: Eighth Korean Mathematical Olympiad (Crux Math. Dec 1999)
(In reply to
Analytic Solution by Brian Smith)
But
2^6 * 3^11 + 2^8 * 3^9 + 2^10 * 3^7 + 2^16 * 3^2 + 2^12 * 3 = 19217856
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Posted by Charlie
on 2017-10-15 21:16:32 |