Let
m*n=w (i)
m is a 3-digit number
so is n
w is a 6-digit number
In equation (i) only 4 distinct digits are used.
Find the possible equations.
(In reply to
Too many - here's some by Jer)
I admit that the multitude of solutions complying with the puzzle's requirements came as a total surprise to me .
However it is bound to happen now and then if neither the author nor the reviewers solve the puzzle "comme il faut".
Still - there is a happy ending:
<begin a new puzzle - courtesy of jer>
A 3-digit number m and its square are expressed only by 4 distinct non-zero digits e.g. 472*472=222784 ==> 2,4,7,8 .
There are many numbers with this feature, however you are requested to find m such that both m-1 and m+1 need only
4 non-zero digits when concatenated with their respective squares.
<end>
Thanks, jer - you like it and I like it too.
Now is Charlie's turn to establish whether this time it's a unique solution or not.
HOO NOSE?
Edited on December 3, 2017, 11:24 am
re: Too many - here's some
