Let AB and PQ be chords of circle Γ where AB is arbitrary and
PQ is the perpendicular bisector of AB. Let C be a point on Γ
distinct from points A and B. Let I be the incenter of ΔABC. Let
H be the intersection of the perpendicular bisectors of line segments
IA and IB.
Prove that H is either the point P or the point Q.
I agree that the ray CI intersects the line PQ at point P and the point H ( the intersection of the perpendicular bisectors of line segments IA and IB ) lies on line PQ, but why does P = H?
I know why now, that's why I edited my first post.
re: Solution
