A number consisting of 2 identical digits, say
xx is multiplied by
99.
Write down the product P, given its tens digit (i.e. 3rd from the left) is y.
P&P only.
xx*99=(10x+x)*(100-1)=1000x+100x-10x-x=xx00-xx
xx00 - xx = (x, x-1, 10-(x+1), 10-x)
If 10-(x+1)=y => 10-x=y+1; x-1=8-y; x=9-y
P= (9-y,8-y,y,y+1)
Verifying:
99*77: x=7: y=10-(x+1)=2
P= (9-2, 8-2, 2, 2+1) = 7623
Edited on February 26, 2018, 8:42 am
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Posted by armando
on 2018-02-26 08:41:13 |