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All in the USA (Posted on 2018-03-20) Difficulty: 3 of 5
EXZBY+FAEFA+CGBZAE+ZGYB+DEFCE+DBCGXE=XBXBFB

Replace the BOLD LETTERS above by appropriate letters of English ABC
- you'll get a nice alphametic puzzle based on seven US Cities.

List the cities, their states and solve the alphametic.

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution computer solution Comment 2 of 2 |
Starting with seeing XBXBFB as KOKOMO from its quite apparent pattern, then EXZBY as AKRON, Reno and Tampa fall into place, etc. and I get:

AKRON MIAMI PEORIA RENO TAMPA TOPEKA KOKOMO
EXZBY FAEFA CGBZAE ZGYB DEFCE DBCGXE XBXBFB

either of which solves to

47918+50450+261904+9681+34524+312674=717151


The program shown at bottom presents, for the cities in order:

 5836 74074 193840 8963 20710 231950 535373
 47918 50450 261904 9681 34524 312674 717151
 19832 65165 43851 8423 71601 730491 939363
 
The first row has 0 for the leading A in AKRON, and the last row has 0 for the leading P in PEORIA. Only the middle row has no leading zeros.


DefDbl A-Z
Dim crlf$, s$


Private Sub Form_Load()
 Form1.Visible = True
 Text1.Text = ""
 crlf = Chr(13) & Chr(10)
 
 s$ = "AKRONMIPET"
 h$ = s
 Do
   akron = conv("AKRON")
   miami = conv("MIAMI")
   peoria = conv("PEORIA")
   reno = conv("RENO")
   tampa = conv("TAMPA")
   topeka = conv("TOPEKA")
   kokomo = conv("KOKOMO")
   
   If akron + miami + peoria + reno + tampa + topeka = kokomo Then
     Text1.Text = Text1.Text & Str(akron) & Str(miami) & Str(peoria) & Str(reno) & Str(tampa) & Str(topeka) & Str(kokomo) & crlf
   End If
   
   DoEvents
   permute s
 Loop Until s = h
  
 Text1.Text = Text1.Text & crlf & ct & " done"
  
End Sub

Function conv(x$)
  v$ = ""
  For i = 1 To Len(x)
    ix = InStr(s$, Mid(x, i, 1))
    v = v + LTrim(Str(ix - 1))
  Next
  conv = Val(v)
End Function


  Posted by Charlie on 2018-03-20 15:05:39
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