Found on the web:
begin
260723233115686*1931
43744839742282591947
1181326544136*5138222
186378732807587076747
519650114814905002347

Any three of these numbers add up to a perfect square.
end

I have no means to check whether it is a true statement and revised
just 3 possible combinations by adding mod 100 the 2 last digits, i.e. 47+47+47= 41, 47+47+22=96 and 47+47+31=25.
I leave it to the solvers to check the 10 possible combinations and to explain what means were used and what was the runtime.
To make it more interesting 2 distinct digits I've replaced by an asterisk "*".

Have fun finding if the statement is true!
If so - for what values of the asterisks?

(In reply to re: computer solution by Charlie)

You wrote and ran this program in Basic on a smartphone?  That sounds like an awful pain in the neck.

Posted by Jer on 2018-05-19 23:26:57