Find a six-digit number
ABCDEF such that
AB3+CD3+EF3=ABCDEF.
Rem: VWXYZ denotes the value of the string (not necessarily distinct digits).
(In reply to
computer solution by Charlie)
Given the standard definition of an n-digit number the A in the numeric strings ABCDEF must be a non-zero digit and each of A, B, C, D, E, and F are decimal digits yet there is no more than an assumption that the C and E digits are also non-zero digits. Given that these two-digit strings can have leading zeroes, the following five solutions can be included with the seven already given:
336700
336701
340067
407000
407001
If each digit were given as distinct, there are two solutions:
341067
487215
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Posted by Dej Mar
on 2018-06-12 22:50:09 |
re: computer solution
