Nine circles of radius 0.5 are externally tangent to a circle of radius 1 and also are tangent to one another.
Find the distance between the centers of the first and the last of the smaller circles.
sin((360-8*2*arcsin(0.5/1.5))/2)*1.5*2
Which simplifies to
3sin(8arcsin(1/3)) = 1904sqrt(2)/2187
or about 1.231213
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Posted by Jer
on 2018-09-01 13:59:30 |