All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers > Sequences
Emirps census (Posted on 2018-10-12) Difficulty: 2 of 5
An emirp (prime spelled backwards) is a prime number that results in a different prime when its decimal digits are reversed.
This definition excludes the related palindromic primes.

13, 17, 31, 37, 71... are emirps.


List values of q(n) (the number of emirps of length n) for n=2 to 6.

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution computer-aided solution | Comment 1 of 2
The census is shown:

  emirps pal  emirp
              pairs
1     0    4     0
2     8    1     4
3    28   15    14
4   204    0   102
5  1406   93   703
6  9538    0  4769
7 70474  668 35237

 

The first column after the length column shows the number of primes that fit. The next two columns show the number that are palindromes, and then the number of pairs of non-palindromic primes (half the value in column 1). Lengths 4 and 6 have no palindromic primes as palindromes with those numbers of digits would be multiples of 11.



DefDbl A-Z
Dim crlf$, ct(7), pal(7)
Function mform$(x, t$)
  A$ = Format$(x, t$)
  If Len(A$) < Len(t$) Then A$ = Space$(Len(t$) - Len(A$)) & A$
  mform$ = A$
End Function

Private Sub Form_Load()
 Text1.Text = ""
 crlf$ = Chr(13) + Chr(10)
 Form1.Visible = True
 
 p = 1
 Do
   p = nxtprm(p)
   forw$ = LTrim(Str(p))
   rev$ = ""
   For i = 1 To Len(forw$)
     rev = Mid(forw, i, 1) + rev
   Next
   If Len(rev) > 7 Then Exit Do
   If prmdiv(Val(rev)) = Val(rev) Then
     l = Len(rev)
     ct(l) = ct(l) + 1
     If Val(rev) = p Then pal(l) = pal(l) + 1
     If l = 2 Then Text1.Text = Text1.Text & Str(p)
   End If
   DoEvents
 Loop
 
 Text1.Text = Text1.Text & crlf
 
 For l = 1 To 7
   Text1.Text = Text1.Text & l & mform(ct(l) - pal(l), "#####0") & mform(pal(l), "####0")
   Text1.Text = Text1.Text & mform((ct(l) - pal(l)) / 2, "#####0") & crlf
 Next
 
 End Sub
Function prm(i)
  Dim p As Long
  Open "17-bit primes.bin" For Random As #111 Len = 4
  Get #111, i, p
  prm = p
  Close 111
End Function
Function prmdiv(num)
 Dim n, dv, q
 If num = 1 Then prmdiv = 1: Exit Function
 n = Abs(num): If n > 0 Then limit = Sqr(n) Else limit = 0
 If limit <> Int(limit) Then limit = Int(limit + 1)
 dv = 2: GoSub DivideIt
 dv = 3: GoSub DivideIt
 dv = 5: GoSub DivideIt
 dv = 7
 Do Until dv > limit
   GoSub DivideIt: dv = dv + 4 '11
   GoSub DivideIt: dv = dv + 2 '13
   GoSub DivideIt: dv = dv + 4 '17
   GoSub DivideIt: dv = dv + 2 '19
   GoSub DivideIt: dv = dv + 4 '23
   GoSub DivideIt: dv = dv + 6 '29
   GoSub DivideIt: dv = dv + 2 '31
   GoSub DivideIt: dv = dv + 6 '37
 Loop
 If n > 1 Then prmdiv = n
 Exit Function

DivideIt:
 Do
  q = Int(n / dv)
  If q * dv = n And n > 0 Then
    prmdiv = dv: Exit Function
   Else
    Exit Do
  End If
 Loop

 Return
End Function
Function nxtprm(x)
  Dim n
  n = x + 1
  While prmdiv(n) < n Or n < 2
    n = n + 1
  Wend
  nxtprm = n
End Function


  Posted by Charlie on 2018-10-12 12:05:22
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information