I don't know how to do this. It's surely not with the approach I've taken here.
I have done
y=(2x+27b)*b
z=(2y+27c)*c
Then I have arbitrarily give b=c=1 and calculate x so that z^2+27x is a perfect square.
For x=165 y=357 z=741, I get
x^2+27y=192^2
y^2+27z=384^2
z^2+27x=744^2
unfortunately x^2+y^2+z^2+27 is not a perfect square. I can give different values to a and b and search again for new posible values of x, but would be time consuming...
So, this is probably not the way to do this.
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Posted by armando
on 2019-01-23 06:48:24 |