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Duelling pairs (Posted on 2018-11-02)

In poker, suppose you’re dealt a pair.

Is the probability that your opponent also holds a pair higher, lower, or the same as it would be if you held nothing?

No Solution Yet Submitted by Ady TZIDON

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Solution

| Comment 5 of 16 |

If I have a pair then the probability my opponent has a pair is (2*1 + 48*3)/(50*49) = 73/1225.

If I do not have a pair then the probability my opponent has a pair is (6*2 + 44*3)/(50*49) = 72/1225.

Then the probability my opponent holds a pair is higher when I hold a pair verses when I do not hold a pair.

Posted by Brian Smith on 2019-07-04 20:28:27

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