ABCDE is a concave pentagon with angle BCD being concave. Angles BAE, BCD, and CDE are right angles. Given AB=4, BC=3, CD=4, and DE=5, find the length of AE.
BE is the hypotenuse of a triangle with sides 4 and 8 so BE^2=4^2+8^2=80.
Now we have right triangle BAE. 4^2+AE^2=80. AE=8.
Another way to see this is to complete rectangle BCDF. Then triangles BAE and BFE are congruent. FE=AE=8
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Posted by Jer
on 2019-09-03 08:15:00 |
Two solutions
