Let number N be represented by a chain of 50 “ones”.
The 26th “1”, counting from the right,
is replaced by a new digit, say “x”, causing N to become a multiple of 13.
Find x.
Let us denote by T a number consisting of 6 ones I.e. 111111.
Clearly T is divisible by 1001, and therefore by 13, since 1001=7*11*13.
Our number N can be seen as concatenation TTTTTTx1TTTTTT and its divisibility by 13 is exactly as the divisibility of x1.
x=9 makes x1=91 , a multiple of 13.
Therefore the answer is 9.
P.S. It is a d1 puzzle.