(In reply to
Solution by Brian Smith)
Sorry, but I could not reproduce the algebra used for your substitutions involving "x". So, I tried an example. Instead of the 19 and 17 zeros, I went for 4 and 2 zeroes, and I made x correspondingly scaled:
x = 10^2 + 1
The new A and Bs don't agree with the old ones.
rabbit-3:~ lord$ more v.f
program v
x=10**2+1
a=200002./(1002.**2+2)
b=200001./(1001.**2+2)
a1=(200*x+1)/(x**2+2*x+5)
b1=200*x/(x**2+2)
print*,'a a1 ',a,a1
print*,'b b1 ',b,b1
end
rabbit-3:~ lord$ v
a a1 0.199203983 1.94091082
b b1 0.199601203 1.97980988
I changed x to produce the needed number of zeroes and still got disagreement as the LSD gets shifted up:
x=10**3+1
rabbit-3:~ lord$ v
a a1 0.199203983 0.199401796
b b1 0.199601203 0.199799806
Edited on October 27, 2019, 3:11 pm
re: Solution
