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Cube hunting (Posted on 2020-05-29) Difficulty: 3 of 5
Find the set of integers n such that n6 + 24n3 + 192 is a perfect cube.

No Solution Yet Submitted by Danish Ahmed Khan    
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Hints/Tips re: I suspect ... me, I am sure | Comment 3 of 9 |
(In reply to I suspect ... by Larry)

It looks like there is no solution. No need to test 20M numbers.

Since 192=2^6*3^1 you need to check only for the first 7 factors to prove the absence of integer solutions.
On the other hand if the bug in the text is a typo - replace 192 by 191 and show that n=1 is the only number that does it.

I saw instantly that 11+24+191=216=6*6*6.
Since  191 is a prime number the  polynome  has only one non-fraction root.

  Posted by Ady TZIDON on 2020-05-30 05:59:17
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