16p + 1 = x^3
x is odd, and since p=2 isn't a solution p is odd as well.
Factoring, 16p = (x-1)(x^2 + x + 1)
(x-1) is even and won't divide odd p so it divides 16.
Thus, (x-1) can only be 2,4,8,or 16.
The only solution is when x=17 giving p=307 which is prime.
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Posted by xdog
on 2020-07-14 07:33:30 |