Let ABCD be a parallelogram with AB>BC and ∠DAB less than ∠ABC. The perpendicular bisectors of sides AB and BC intersect at the point M lying on the extension of AD. If ∠MCD is equal to 15 degree, find the measure of ∠ABC
(In reply to
Solution by Larry)
I see why you don't do Geometry problems:
angle AMC is pi - (pi - x + 15)
Using radians and degrees in the same expression is... unexpected.
My solution is worked out in degrees but is otherwise the same.
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Posted by Jer
on 2020-12-26 11:10:54 |
re: Solution
