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Go one, two, three (Posted on 2021-01-09)

Solve in natural numbers a²=2^b3^c+1

No Solution Yet Submitted by Danish Ahmed Khan

Rating: 3.0000 (1 votes)

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computer exploration (spoilers)

| Comment 1 of 6

clc

for t=0:1000

for b=0:1000

if b>0

c=t-b;

if c>0

asq=(2^b*3^c+1);

if asq<1e15

sr=round(sqrt(asq));

if sr*sr==asq

disp([sr b c])

end

finds

     a     b     c
     5     3     1
     7     4     1
    17     5     2

Posted by Charlie on 2021-01-09 11:20:47

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