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Thirds and Differences (Posted on 2005-07-21) Difficulty: 2 of 5

Arrange the digits 1-9 so that the first 3 form a number that is 1/3 of the number formed by the last three and the three digits in the middle form a number that is the difference between them.

The numbers are as they appear, not summed.

No Solution Yet Submitted by Erik O.    
Rating: 3.0000 (3 votes)

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Solution Python solution | Comment 10 of 12 |
192 384 576
219 438 657
273 546 819
327 654 981

------ Python code follows ------
from itertools import permutations

nums = [1,2,3,4,5,6,7,8,9]
for j in permutations(nums):
    x = 100*j[0] + 10*j[1] + j[2]
    y = 100*j[3] + 10*j[4] + j[5]
    z = 100*j[6] + 10*j[7] + j[8]
    if z != 3*x:
        continue
    if y != z-x:
        continue
    print(x,y,z)

  Posted by Larry on 2021-02-26 16:29:58
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