The sum of the first 9 primes is 100, so for there to be a solution with 9 distinct primes we'd need to replace one of them with a prime that is 1 greater, which isn't possible. Therefore the largest possible solution would be when n = 8, which is easily found as the first 7 primes + 43.
2 + 3 + 5 + 7 + 11 + 13 + 17 + 43 = 101
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Posted by tomarken
on 2021-06-16 07:44:34 |