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Pascal's Lottery (Posted on 2021-07-01) Difficulty: 3 of 5

Every soul is allotted 6 numbers, chosen at random from the positive integers.

If such numbers are relatively prime, then the soul is admitted to Heaven - otherwise, not.

What is the probability of an eternal reward?

What is the probability of an eternal reward, if such numbers must be pairwise prime?

Note: the integers 30, 42, 70, and 105 are relatively prime, while the numbers 121, 122, and 123 are pairwise prime, see the definitions at https://primes.utm.edu/glossary/xpage/RelativelyPrime.html

No Solution Yet Submitted by broll    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: partial solution and some thoughts Comment 6 of 6 |
(In reply to partial solution and some thoughts by Charlie)

I agree with your idea for the second part.  Of note is that the 1/p term cancels if you expand and simplify


((1-1/p)^6 + 6*(1/p)*((p-1)/p)^5)

becomes 

1 - 15/p^2 + 40/p^3 - 45/p^4 +24/p^5 - 5/p^6

Since you are taking the product of terms it's good that these converge quickly to 1, but I don't know the convergence rules for infinite products.

Our answers may yet agree.


  Posted by Jer on 2021-07-01 17:38:53
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