What is the minimal number of “ones” needed
to express
the following 6 numbers:
6, 9, 18, 45, 60, 265.
You may use only the following symbols, each symbol up to three times
and any quantity of brackets .
+ - / * ^ !
$ Sum of digits.
. Decimal point
Sqrt Square root.
and concatenation (of numbers only)
Sum up the total of ones and publish your answer.
Examples:
37=111/(1+1+1). Scores 6
48=((1+1+1)!)!! Scores 3
List your 6 formulas.
NB: The order of candidate numbers is not by the level of difficulty
6 = (1+1+1)!
3!
score 3
9 = 11-1-1
score 4
18 = (11-1-1)(1+1)
9*2
score 6
45 = $((11-1)^((1+1+1)!-1))
$(10^(3!-1)-1)
$99999
score 7
60=(1+1+1)!*(11-1)
6*10
score 6
265=(11)*((1+1)^(1+1))!+1
11*(2^2)!+1
11*24+1
score 7
Total=33
Not using more than 3 plus signs makes it tough, but I found ways around this.
Edit to remove concatenation symbol as is isn't needed and to fix 265
Edited on July 14, 2021, 7:54 am
|
Posted by Jer
on 2021-07-13 16:26:15 |