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Common Birth Dates II (Posted on 2021-11-17) Difficulty: 3 of 5
Common Birth Dates asked for the expected number of pairs of common birth dates for a cohort of 1000 people whose ages were clustered around a certain value.

Now consider a similar question to the traditional birthday problem: If you attend a concert or other event where people tend to be of a similar age, how large would such an event need to be in terms of number of attendees, so that you'd have at least a 50% probability that there would be at least two people born on the exact same day (year, month and day)?

Again to make things specific: assume the standard deviation about whatever the mean age to be is 12 years and it follows a normal distribution.

Again feel free to vary the assumptions about the distribution.

See The Solution Submitted by Charlie    
Rating: 4.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
explanation of discrepancy | Comment 3 of 6 |
I think my analytic expression is incorrect. Take the simpler problem of a "day of the year" birthday problem with a uniform distribution P(i) = 1/365. The expression for n people taking into account conditional probabilities is:

P(match) = 1-P(no matches in n people)

= 1 - (364/365)(363/365)...(365-n+1)/365) = 1 - n! (365 n)/365^n

which is  0.507 for n=23

My errant formulation (which ignores conditional probability) would be here:

ppair (one pair with no match) = Sum(m=1,365) (1/365)(364/365)
= 364/365, and so
P(match) = 1-(ppair)^(n(n-1)/2) = 1 - (354/365)^(n(n-1)/2)

For n=23 this is:
P(match) = 1 - 0.49952 = 0.50048
which is an underestimate this time..... a different answer nonetheless.

So for the analytic I need to consider an expression that uses conditional probabilities.....

Edited on November 19, 2021, 10:46 am
  Posted by Steven Lord on 2021-11-19 10:16:47

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