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sum, reciprocals, squares (Posted on 2022-03-22) Difficulty: 2 of 5
The sum of two numbers is 1.

The sum of the reciprocals of the numbers is 1.

Find the sum of the squares of the numbers (without finding the numbers themselves.)

What do you notice?

No Solution Yet Submitted by Jer    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
What I have noticed Comment 4 of 4 |
x+y=1
(1/x)+(1/y)=1
(x/xy)+(y/xy)=1
xy=1
y=1/x
x+(1/x)=1

This has no solutions in real numbers, so I have noticed that x and y are not real.


  Posted by Math Man on 2022-03-22 20:55:38
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