Find a number ABCDEFGHIJ, with all its digits different, such that:
- A, C, E, G, and I are odd
- HIJ is a multiple of BCD
- GH is a multiple of AB
- HIJ/BCD equals GH/AB
(In reply to
This is unique also 3218709654 by saurabh)
While your comment may be accurate the same does NOT hold true corresponding to your mode of response which clearly displays the answer in the subject and, thereby violating the fundamental tenets governing this website.
Edited on April 22, 2022, 12:52 pm