All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Logic
No doubles (Posted on 2022-05-02) Difficulty: 2 of 5
Can you create a subset of (1, 2, 3, ..., 3k) such that none of its 2k-1 members is twice the value of another?

Either provide such a set or show none exists.

Inspired by: Austrian-Polish Math. Competition.

See The Solution Submitted by Ady TZIDON    
Rating: 4.5000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(3): Idea, no proof | Comment 6 of 10 |
(In reply to re(2): Idea, no proof by Jer)

Unless I am mistaken, for k=42, doesn't your method show that there are *more* than 2k-1 (in this case, 2k) members in the solution set?  It's easy to see your solution is correct.  Maybe the problem statement is incorrect?
  Posted by Kenny M on 2022-05-02 15:22:59

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information