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Beyond Fermat (Posted on 2008-05-05) Difficulty: 3 of 5
To show that Fermat's Last Theorem applies only to sums of two terms, Fred asked his friends, Alice, Bob, Carol and Diane, to list three perfect cubes that added up to another perfect cube. Each came up with his or her own list, different from the others'.

All except Diane limited their lists of three cubes to the first 12 cubes. Alice and Bob had two of the same numbers in their lists, but Carol's list had no numbers in common with either of those lists.

Diane, not limiting herself to the first 12 cubes, did use in her list two of the sums from among the three sums of cubes found by Alice, Bob and Carol.

What were Carol's and Diane's lists of cubes?

See The Solution Submitted by Charlie    
Rating: 3.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Puzzle Answer Comment 4 of 4 |
The list of cubes owned by the two individuals are as follows:
CAROL: 27,74,125
DIANE: 729, 1728, 3375

*** I sincerely hope to posit an independent explanation to this very interesting puzzle.

  Posted by K Sengupta on 2022-05-12 23:06:43
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