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Bob's Cab (Posted on 2009-03-02) Difficulty: 3 of 5
Cab driver Bob mentioned to his friend Jim that he recently drove three passengers in his cab, that the product of their (the passengers') ages was 2450, and that the sum of their ages was exactly twice Jim's age.

From this, Jim couldn't deduce what their three ages were.

But when Bob added that he was younger than at least one of the passengers, Jim, who knew Bob's age, was able to deduce all the passengers' ages.

What were Bob's and Jim's ages, and the ages of the passengers?

See The Solution Submitted by Charlie    
Rating: 4.0000 (1 votes)

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Solution Explanation to Puzzle Answer Comment 5 of 5 |
(In reply to Puzzle Answer by K Sengupta)

At the outset we need to determine 3 positive integer whose product is 2450.

Case 1: Precisely one of the numbers is 1
Only 1, 1, 2450 is possible

Case 2: Precisely two of the numbers is 1
Eight triplets are possible,  and these are:
1, 2, 1225              1, 14, 175
1, 5, 490                 1, 25, 90
1, 7, 350                 1, 35, 70
1, 10, 245               1, 49, 50

Case 3: None of the three numbers is a 1
Since 2450 = 2* 5^2 * 7^2, it follows that the prime factors are 2, 5 and 7
So, the valid  triplets are posited hereunder as follows:
2, 4, 5                       5, 10, 49
2, 7, 175                   5, 14, 35
2, 25, 49                   7, 1, 50
2, 35, 35                   7, 10, 35
5, 5, 98                     7, 14, 25
5, 7, 70

We now consider the sum of each of the 20 triplets as follows:

T r I p l e t             SUM
----------------            --------
1, 1, 2450             2452
1, 2, 1225             1228
1, 5, 490                 496
1, 7, 350                 358
1, 10, 245               256
1, 14, 175               190
1, 25, 98                 124
1, 35, 70                 106    
1, 49, 50                 100
2, 5, 245                 252
2, 7, 175                 184
2, 25, 49                   76
2, 35, 35                   72
5, 5, 98                    108
5, 7, 70                      82
5, 10, 49                    64
5, 14, 35                    54
7, 7, 50                      64
7, 10, 35                    52
7, 14, 25                    46

Now, Bob mentioned to Jim that the sum of the ages of the passengers is precisely twice the age of Jim whereupon Jim expressed his inability to deduce their age.
         Since Jim knows his own age, and therefore the sum of the three ages, this means the sum is NOT sufficient to identify the three ages. In other words, the sum corresponds to two different triplets.
         The only sum that is repeated is 64, corresponding to:
• 5+10+49=64
• 7+7+50= 64
So there is precisely one adult passenger, whose correct age corresponds to the third element of one of the abovementioned triplets. 
               We now remember that Bob mentioned that he was younger than one of the passengers. So the incorrect age of the adult passenger (which is equal to Bob's age) is less than the correct age of the said passenger. This is only possible when:
Passenger's age = 50
Bob's age = 49 

Also, ages of other 2 cab passengers = 7, and 7
Also,  2* (Jim's age) = 64
=> Jim's age = 32

Consequently,  summarizing the foregoing we have:
• Jim's age = 32
• Bob's age = 49
• Ages of the three passengers = 7, 7, and 50

Edited on June 15, 2022, 9:02 am
  Posted by K Sengupta on 2022-06-15 07:37:43

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