Choose two distinct non-zero digits.
Evaluate the sum of the product and
the s.o.d. of the pair.
What is the probability that the result is the concatenation of the initially selected digits?
Example: if the digits were 4,7 the resulting 4*7+7+4=39, not the case you were after, i.e. 47 or 74
(In reply to
Solution by Larry)
Choose the two digit number concatenated as ab. Which is actually 10a+b. Then we have
10a+b=ab+a+b
10a=ab+a (one solution is a=0. If a<>0 then)
10=b+1
9=b
and all of your results follow.
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Posted by Jer
on 2022-06-17 09:46:16 |