(In reply to
Puzzle Answer by K Sengupta)
Considering each members of the sequence as nase 3 integers and converting them to base 3, we have:
1,4,9,16,25,36
each of which is a perfect square.
The next two perfect squares are 49 and 64, which are respectably 1211 and 2101 in base 3.
Consequently, the required next two terms are 1211 and 2101.
Edited on August 1, 2022, 10:30 pm