Determine the
minimum value of a prime number p such that there are positive integers
x and
y satisfying this equation:
x2 + p3 = y4
*** As an extra challenge only, solve this puzzle without using a computer program/spreadsheet aided method.
p^3 = (y^2-x)(y^2+x)
p's only factors are 1 and p, so y^2-x = 1, or x = (y^2-1)
Then p^3 = (y^2-(y^2-1))(y^2+(y^2-1)) = 2y^2-1, a familiar form.
{1,1}, {23,78} are the smallest integer solutions.
Checking: 23^3=2*78^2-1
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Posted by broll
on 2022-08-14 12:07:50 |